Largest & Smallest Digits Difference

Largest & Smallest Digits Difference 

PROBLEM STATEMENT :

A number N is passed as the input. The program must print the difference between the largest and the smallest digits in the number. 

Input Format: The first line will contain the number N. 

Boundary Conditions: 10 <= N <= 99999999 

Output Format: The difference between the largest and the smallest digits in the number N. 

Example Input/Output 1: 

Input: 2501 

Output: 5 

Explanation: The largest digit is 5. The smallest digit is 0. The difference is 5-0 = 5 is printed as the output. 

Example Input/Output 2: 

Input: 22 

Output: 0 

Explanation: Both the largest and the smallest digit is 2. Hence the difference 2-2 = 0 is printed as the output.

SOLUTION :

C (Programming Language)

       
#include<stdio.h>
#include<stdlib.h>

int main()
{
    int n,min,max,u;
    scanf("%d",&n);
    min=n%10;
    max=n%10;
    while(n)
    {
        u=n%10;
        if(u>max) max=u;
        if(u<min) min=u;
        n/=10;
    }
    printf("%d",max-min);
}
 

C++ (CPP)

       
#include <iostream>
 
using namespace std;

int main(int argc, char** argv)
{
    int n,min,max,u;
    cin>>n;
    min=n%10;
    max=n%10;
    while(n)
    {
        u=n%10;
        if(u>max) max=u;
        if(u<min) min=u;
        n/=10;
    }
    cout<<max-min;
}
 

JAVA

       
import java.util.*;
public class Hello {

    public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt(),min,max,u;
		min=n%10;
		max=n%10;
		while(n>0)
		{
		    u=n%10;
		    if(u>max) max=u;
		    if(u<min) min=u;
		    n/=10;
		}
		System.out.println(max-min);
	}
}
 

PYTHON

       
n=input()
print(int(max(n))-int(min(n)))
 

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