Shift Characters Upwards

 Shift Characters Upwards 

PROBLEM STATEMENT :

The program must accept N string values of equal length L and an integer K as the input. The program must perform the following operation K times. - Shift the middle L-2 characters towards the top by one position among the given N string values. Finally, the program must print the N modified string values as the output. 

Boundary Condition(s):

2 <= N <= 100 

3 <= Length of each string <= 100 

1 <= K <= 10^8 

Input Format: 

The first line contains N. 

The next N lines, each contains a string value. 

The (N+2)nd line contains K. 

Output Format: 

The first N lines containing the N modified string values. 

Example Input/Output 1: 
Input: () 
5 
coding 
across 
expert 
office 
travel 
1  
Output: 
ccrosg 
axpers 
effict 
oravee 
todinl 

Explanation: 

Here N = 5 and K = 1. 

The length of each string is 6. 

K = 1: After shifting the middle 4(6-2) characters towards the top by one position, the string values become 

ccrosg 

axpers 

effict 

oravee 

todinl 

Example Input/Output 2: 
Input: () 
5 
coding 
across 
expert 
office 
travel 
2  
Output: 
cxperg 
affics 
eravet 
oodine 
tcrosl

---

SOLUTION :

C (Programming Language)

      
#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int main()
{
    int n,i,j,k,shift;
    scanf("%d",&n);
    char s[1001][1001],temp[1001];
    for(i=0;i<n;++i)
    {
        scanf("%s",s[i]);
    }
    scanf("%d",&k);
    k=k%n;
    for(i=0;i<n;++i)
    {
        printf("%c",s[i][0]);
        shift=(i+k)%n;
        for(j=1;j<strlen(s[shift])-1;++j)
        {
            printf("%c",s[shift][j]);
        }
        printf("%c",s[i][strlen(s[i])-1]);
        printf("\n");
    }
}
 

C++ (CPP)

       
#include <bits/stdc++.h>
 
using namespace std;

int main(int argc, char** argv)
{
    int n,i,k;
    cin>>n;
    string s[n],res;
    for(i=0;i<n;++i)
    {
        cin>>s[i];
    }
    cin>>k;
    for(i=0;i<n;++i)
    {
        string res=s[i][0]+s[(i+k)%n].substr(1,s[i].size()-2)+s[i][s[i].size()-1];
        cout<<res<<"\n";
    }
}
 

JAVA

       
import java.util.*;
public class Hello {

    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt(),i;
        String[] s=new String[n];
        for(i=0;i<n;++i)
        {
            s[i]=sc.next().trim();
        }
        int k=sc.nextInt();
        for(i=0;i<n;++i)
        {
            String a=s[i].charAt(0)+"";
            String b=s[(i+k)%n].substring(1,s[(i+k)%n].length()-1);
            String c=s[i].charAt(s[i].length()-1)+"";
            String res=a+b+c;
            System.out.println(res);
        }
   }
}
 

PYTHON

       
import copy
n=int(input())
l=[list(input().strip()) for i in range(n)]
res=copy.deepcopy(l) #For copying the list with seperate object
k=int(input())
k=k%n;
for i in range(n):
    res[i][1:-1]=l[(i+k)%n][1:-1]
for i in res:
    print(*i,sep='')
 

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