String Palindrome

 String Palindrome 

PROBLEM STATEMENT :

A string S is passed as input to the program. The program must print "yes" if the string S is a palindrome and must print "no" if the string is NOT a palindrome. 

Boundary Condition(s): 

1<=length(S)<=10000

Input Format: 

The first line will contain the value of the string S. 

Output Format:

The first line in the output should contain "yes" or "no" based on the input.

Example Input/Output 1: 
Input: () 
malayalam
Output: 
yes 

Example Input/Output 2: 
Input: () 
manager
Output: 
no 

---

SOLUTION :

C (Programming Language)

      
#include<stdio.h>
#include<stdlib.h>

int main()
{
    char s[1001],r[1001],t;
    int l,i=0;
    scanf("%s%n",s,&l);
    strcpy(r,s);
    l-=1;
    while(i<l)
    {
        t=s[i];
        s[i]=s[l];
        s[l]=t;
        i++;
        l--;
    }
    if(strcmp(s,r)==0) printf("yes");
    else printf("no");
}
 

C++ (CPP)

       
#include <iostream>
#include<algorithm> //For reverse function
using namespace std;

int main(int argc, char** argv)
{
    string s,r;
    cin>>s;
    r=s;
    reverse(s.begin(),s.end());
    if(s==r) cout<<"yes";
    else cout<<"no";
}
 

JAVA

       
import java.util.*;
public class Hello {

    public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		String s=sc.next();
		String rev=new StringBuilder(s).reverse().toString();
		if(s.compareTo(rev)==0) System.out.println("yes");
		else System.out.println("no");
	}
}
 

PYTHON

       
s=input()
rev=s[::-1]
print("yes" if s==rev else "no")
 

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